This is very useful and is effectively dividing out the in the . A very common case of this theorem is when then it simplifies to .
The intuition is that we first consider “What primes contributes to the “. Then can only “contribute” from what is left being .
Proof:
We will go prime by prime. Fix a prime . Then let . The power of in is . We can make this power of with . So we get .
Proof:
Let then with . Then
Then let and with we must have hence . Substituting that in and writing as we get as required.